MATH SOLVE

2 months ago

Q:
# Layla and Aidan are selling cases of drinks for a fund raiser. Customers can buy either fruit punch or lemonade. Aidan sold 6 cases of fruit punch and 4 cases of lemonade for a total of $80. Layla sold 6 cases of fruit punch and 5 cases of lemonade for $94. How much is a case of lemonade and how much is a case of fruit punch?

Accepted Solution

A:

Cost of case of lemonade is $14 and cost of case of fruit punch is $4Solution:Let the cost of fruit punch be $ m and cost of lemonade be $ nAidan sold 6 cases of fruit punch and 4 cases of lemonade for a total of $80. Thus we get,[tex]6 \times m+4 \times n=80[/tex]6m + 4n = 80 ----- eqn (1)
Layla sold 6 cases of fruit punch and 5 cases of lemonade for $94. [tex]6 \times m+5 \times n=94[/tex]6m + 5n = 94 ------ eqn (2)So, now, subtract (1) from (2)(2) ⇒ 6m + 5n = 94 (1) ⇒ 6m + 4n = 80 (-) -------------------------
0 + n = 14 n = 14Now, substitute "n" value in (1)6m + 4(14) = 80 6m + 56 = 80 6m = 24 m = 4
Hence, cost of case of lemonade is $14 and cost of case of fruit punch is $4